3+4(2y-2)=-2(6y-2)+8y

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Solution for 3+4(2y-2)=-2(6y-2)+8y equation: 



3+4(2y-2)=-2(6y-2)+8y

We move all terms to the left:

3+4(2y-2)-(-2(6y-2)+8y)=0

We multiply parentheses

8y-(-2(6y-2)+8y)-8+3=0



We calculate terms in parentheses: -(-2(6y-2)+8y), so:

-2(6y-2)+8y

We add all the numbers together, and all the variables

8y-2(6y-2)

We multiply parentheses

8y-12y+4

We add all the numbers together, and all the variables

-4y+4

Back to the equation:

-(-4y+4)



We add all the numbers together, and all the variables

8y-(-4y+4)-5=0

We get rid of parentheses

8y+4y-4-5=0

We add all the numbers together, and all the variables

12y-9=0

We move all terms containing y to the left, all other terms to the right

12y=9

y=9/12

y=3/4

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