-7(w+3)=3w-5+2(2w+1)

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Solution for -7(w+3)=3w-5+2(2w+1) equation: 



-7(w+3)=3w-5+2(2w+1)

We move all terms to the left:

-7(w+3)-(3w-5+2(2w+1))=0

We multiply parentheses

-7w-(3w-5+2(2w+1))-21=0



We calculate terms in parentheses: -(3w-5+2(2w+1)), so:

3w-5+2(2w+1)

determiningTheFunctionDomain
3w+2(2w+1)-5

We multiply parentheses

3w+4w+2-5

We add all the numbers together, and all the variables

7w-3

Back to the equation:

-(7w-3)



We get rid of parentheses

-7w-7w+3-21=0

We add all the numbers together, and all the variables

-14w-18=0

We move all terms containing w to the left, all other terms to the right

-14w=18

w=18/-14

w=-1+2/7

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