3+3(k+4)=6(k-2)+9

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Solution for 3+3(k+4)=6(k-2)+9 equation: 



3+3(k+4)=6(k-2)+9

We move all terms to the left:

3+3(k+4)-(6(k-2)+9)=0

We multiply parentheses

3k-(6(k-2)+9)+12+3=0



We calculate terms in parentheses: -(6(k-2)+9), so:

6(k-2)+9

We multiply parentheses

6k-12+9

We add all the numbers together, and all the variables

6k-3

Back to the equation:

-(6k-3)



We add all the numbers together, and all the variables

3k-(6k-3)+15=0

We get rid of parentheses

3k-6k+3+15=0

We add all the numbers together, and all the variables

-3k+18=0

We move all terms containing k to the left, all other terms to the right

-3k=-18

k=-18/-3

k=+6

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