3(x-3)=8-(x+2)

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Solution for 3(x-3)=8-(x+2) equation: 



3(x-3)=8-(x+2)

We move all terms to the left:

3(x-3)-(8-(x+2))=0

We multiply parentheses

3x-(8-(x+2))-9=0



We calculate terms in parentheses: -(8-(x+2)), so:

8-(x+2)

determiningTheFunctionDomain
-(x+2)+8

We get rid of parentheses

-x-2+8

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

3x+1x-6-9=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

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