3+3(2u-1)=-5(3u-2)+3u

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Solution for 3+3(2u-1)=-5(3u-2)+3u equation: 



3+3(2u-1)=-5(3u-2)+3u

We move all terms to the left:

3+3(2u-1)-(-5(3u-2)+3u)=0

We multiply parentheses

6u-(-5(3u-2)+3u)-3+3=0



We calculate terms in parentheses: -(-5(3u-2)+3u), so:

-5(3u-2)+3u

We add all the numbers together, and all the variables

3u-5(3u-2)

We multiply parentheses

3u-15u+10

We add all the numbers together, and all the variables

-12u+10

Back to the equation:

-(-12u+10)



We add all the numbers together, and all the variables

6u-(-12u+10)=0

We get rid of parentheses

6u+12u-10=0

We add all the numbers together, and all the variables

18u-10=0

We move all terms containing u to the left, all other terms to the right

18u=10

u=10/18

u=5/9

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