3(6z-1)-2(z+7)=3(z+1)

Solution for 3(6z-1)-2(z+7)=3(z+1) equation:

3(6z-1)-2(z+7)=3(z+1)

We move all terms to the left:

3(6z-1)-2(z+7)-(3(z+1))=0

We multiply parentheses

18z-2z-(3(z+1))-3-14=0


We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)


We add all the numbers together, and all the variables

16z-(3z+3)-17=0

We get rid of parentheses

16z-3z-3-17=0

We add all the numbers together, and all the variables

13z-20=0

We move all terms containing z to the left, all other terms to the right

13z=20

z=20/13

z=1+7/13