3+20(2x-40)=37x+1/2-(-9-5x)+4-5

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Solution for 3+20(2x-40)=37x+1/2-(-9-5x)+4-5 equation: 



3+20(2x-40)=37x+1/2-(-9-5x)+4-5

We move all terms to the left:

3+20(2x-40)-(37x+1/2-(-9-5x)+4-5)=0



Domain of the equation: 2-(-9-5x)+4-5)!=0

We move all terms containing x to the left, all other terms to the right

-(-9-5x)-5)!=-6

x∈R



We add all the numbers together, and all the variables

20(2x-40)-(37x+1/2-(-5x-9)+4-5)+3=0

We multiply parentheses

40x-(37x+1/2-(-5x-9)+4-5)-800+3=0

We multiply all the terms by the denominator


40x*2-(-5x-9)-5)-(37x-(-5x-9)-5x+4+1+4-800*2-5)+3*2-(-9)+4-5)=0

We add all the numbers together, and all the variables

-5x+40x*2-(-5x-9)-5)-(37x-(-5x-9)=0

Wy multiply elements

-5x+80x-(-5x-9)-5)-(37x-(-5x-9)=0

We get rid of parentheses

-5x+80x+5x-5)-(37x+5x+9+9=0

We add all the numbers together, and all the variables

85x-5)-(37x+18=0

We move all terms containing x to the left, all other terms to the right

85x-5)-(37x=-18

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