360=(x-3)(12x-25)

Solution for 360=(x-3)(12x-25) equation:

360=(x-3)(12x-25)

We move all terms to the left:

360-((x-3)(12x-25))=0

We multiply parentheses ..

-((+12x^2-25x-36x+75))+360=0


We calculate terms in parentheses: -((+12x^2-25x-36x+75)), so:

(+12x^2-25x-36x+75)

We get rid of parentheses

12x^2-25x-36x+75

We add all the numbers together, and all the variables

12x^2-61x+75

Back to the equation:

-(12x^2-61x+75)


We get rid of parentheses

-12x^2+61x-75+360=0

We add all the numbers together, and all the variables

-12x^2+61x+285=0

a = -12; b = 61; c = +285;
Δ = b2-4ac
Δ = 612-4·(-12)·285
Δ = 17401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{17401}}{2*-12}=\frac{-61-\sqrt{17401}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{17401}}{2*-12}=\frac{-61+\sqrt{17401}}{-24}
$