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3+2(5x+3)=3(x+3)-x
We move all terms to the left:
3+2(5x+3)-(3(x+3)-x)=0
We multiply parentheses
10x-(3(x+3)-x)+6+3=0
We calculate terms in parentheses: -(3(x+3)-x), so:We add all the numbers together, and all the variables
3(x+3)-x
We add all the numbers together, and all the variables
-1x+3(x+3)
We multiply parentheses
-1x+3x+9
We add all the numbers together, and all the variables
2x+9
Back to the equation:
-(2x+9)
10x-(2x+9)+9=0
We get rid of parentheses
10x-2x-9+9=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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