y=2(10-y)-5

Solution for y=2(10-y)-5 equation:

y=2(10-y)-5

We move all terms to the left:

y-(2(10-y)-5)=0

We add all the numbers together, and all the variables

y-(2(-1y+10)-5)=0


We calculate terms in parentheses: -(2(-1y+10)-5), so:

2(-1y+10)-5

We multiply parentheses

-2y+20-5

We add all the numbers together, and all the variables

-2y+15

Back to the equation:

-(-2y+15)


We get rid of parentheses

y+2y-15=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5