3+2(4x-13)=-40x+7

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Solution for 3+2(4x-13)=-40x+7 equation: 



3+2(4x-13)=-40x+7

We move all terms to the left:

3+2(4x-13)-(-40x+7)=0

We multiply parentheses

8x-(-40x+7)-26+3=0

We get rid of parentheses

8x+40x-7-26+3=0

We add all the numbers together, and all the variables

48x-30=0

We move all terms containing x to the left, all other terms to the right

48x=30

x=30/48

x=5/8

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