20w+28=4(2w+31)

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Solution for 20w+28=4(2w+31) equation: 



20w+28=4(2w+31)

We move all terms to the left:

20w+28-(4(2w+31))=0



We calculate terms in parentheses: -(4(2w+31)), so:

4(2w+31)

We multiply parentheses

8w+124

Back to the equation:

-(8w+124)



We get rid of parentheses

20w-8w-124+28=0

We add all the numbers together, and all the variables

12w-96=0

We move all terms containing w to the left, all other terms to the right

12w=96

w=96/12

w=8

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