8(x+1)-4=6x+2(3+x)

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Solution for 8(x+1)-4=6x+2(3+x) equation: 



8(x+1)-4=6x+2(3+x)

We move all terms to the left:

8(x+1)-4-(6x+2(3+x))=0

We add all the numbers together, and all the variables

8(x+1)-(6x+2(x+3))-4=0

We multiply parentheses

8x-(6x+2(x+3))+8-4=0



We calculate terms in parentheses: -(6x+2(x+3)), so:

6x+2(x+3)

We multiply parentheses

6x+2x+6

We add all the numbers together, and all the variables

8x+6

Back to the equation:

-(8x+6)



We add all the numbers together, and all the variables

8x-(8x+6)+4=0

We get rid of parentheses

8x-8x-6+4=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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