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3+(4-x)(x+1)=159-x2
We move all terms to the left:
3+(4-x)(x+1)-(159-x2)=0
We add all the numbers together, and all the variables
-(-1x^2+159)+(-1x+4)(x+1)+3=0
We get rid of parentheses
1x^2+(-1x+4)(x+1)-159+3=0
We multiply parentheses ..
1x^2+(-1x^2-1x+4x+4)-159+3=0
We add all the numbers together, and all the variables
x^2+(-1x^2-1x+4x+4)-156=0
We get rid of parentheses
x^2-1x^2-1x+4x+4-156=0
We add all the numbers together, and all the variables
3x-152=0
We move all terms containing x to the left, all other terms to the right
3x=152
x=152/3
x=50+2/3
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