3+(1/4)a=31a=

Solution for 3+(1/4)a=31a= equation:

3+(1/4)a=31a=

We move all terms to the left:

3+(1/4)a-(31a)=0


Domain of the equation: 4)a!=0

a!=0/1

a!=0

a∈R


We add all the numbers together, and all the variables

(+1/4)a-31a+3=0

We add all the numbers together, and all the variables

-31a+(+1/4)a+3=0

We multiply parentheses

a^2-31a+3=0

a = 1; b = -31; c = +3;
Δ = b2-4ac
Δ = -312-4·1·3
Δ = 949
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{949}}{2*1}=\frac{31-\sqrt{949}}{2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{949}}{2*1}=\frac{31+\sqrt{949}}{2}
$