3u+4-5(-2u-1)=5(u-1)

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Solution for 3u+4-5(-2u-1)=5(u-1) equation:



3u+4-5(-2u-1)=5(u-1)
We move all terms to the left:
3u+4-5(-2u-1)-(5(u-1))=0
We multiply parentheses
3u+10u-(5(u-1))+5+4=0
We calculate terms in parentheses: -(5(u-1)), so:
5(u-1)
We multiply parentheses
5u-5
Back to the equation:
-(5u-5)
We add all the numbers together, and all the variables
13u-(5u-5)+9=0
We get rid of parentheses
13u-5u+5+9=0
We add all the numbers together, and all the variables
8u+14=0
We move all terms containing u to the left, all other terms to the right
8u=-14
u=-14/8
u=-1+3/4

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