3+(1/3z)=30

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Solution for 3+(1/3z)=30 equation: 



3+(1/3z)=30

We move all terms to the left:

3+(1/3z)-(30)=0



Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

(+1/3z)+3-30=0

We add all the numbers together, and all the variables

(+1/3z)-27=0

We get rid of parentheses

1/3z-27=0

We multiply all the terms by the denominator


-27*3z+1=0

Wy multiply elements

-81z+1=0

We move all terms containing z to the left, all other terms to the right

-81z=-1

z=-1/-81

z=1/81

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