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2x+3/x+1=6x+5/3x+2
We move all terms to the left:
2x+3/x+1-(6x+5/3x+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x+2)!=0We get rid of parentheses
x∈R
2x+3/x-6x-5/3x-2+1=0
We calculate fractions
2x-6x+9x/3x^2+(-5x)/3x^2-2+1=0
We add all the numbers together, and all the variables
-4x+9x/3x^2+(-5x)/3x^2-1=0
We multiply all the terms by the denominator
-4x*3x^2+9x+(-5x)-1*3x^2=0
We add all the numbers together, and all the variables
9x-4x*3x^2+(-5x)-1*3x^2=0
Wy multiply elements
-12x^3-3x^2+9x+(-5x)=0
We get rid of parentheses
-12x^3-3x^2+9x-5x=0
We do not support expression: x^3
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