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3x+4=1/2x-8
We move all terms to the left:
3x+4-(1/2x-8)=0
Domain of the equation: 2x-8)!=0We get rid of parentheses
x∈R
3x-1/2x+8+4=0
We multiply all the terms by the denominator
3x*2x+8*2x+4*2x-1=0
Wy multiply elements
6x^2+16x+8x-1=0
We add all the numbers together, and all the variables
6x^2+24x-1=0
a = 6; b = 24; c = -1;
Δ = b2-4ac
Δ = 242-4·6·(-1)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-10\sqrt{6}}{2*6}=\frac{-24-10\sqrt{6}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+10\sqrt{6}}{2*6}=\frac{-24+10\sqrt{6}}{12} $
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