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3x+1=(21+3x)/20
We move all terms to the left:
3x+1-((21+3x)/20)=0
We add all the numbers together, and all the variables
3x-((3x+21)/20)+1=0
We multiply all the terms by the denominator
3x*20)-((3x+21)+1*20)=0
We add all the numbers together, and all the variables
3x*20)-((3x+21)=0
Wy multiply elements
60x^2=0
a = 60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·60·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{120}=0$
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