2/3(1x+4)+5x=6x+7

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Solution for 2/3(1x+4)+5x=6x+7 equation: 



2/3(1x+4)+5x=6x+7

We move all terms to the left:

2/3(1x+4)+5x-(6x+7)=0



Domain of the equation: 3(1x+4)!=0

x∈R



We add all the numbers together, and all the variables

2/3(x+4)+5x-(6x+7)=0

We add all the numbers together, and all the variables

5x+2/3(x+4)-(6x+7)=0

We get rid of parentheses

5x+2/3(x+4)-6x-7=0

We multiply all the terms by the denominator


5x*3(x+4)-6x*3(x+4)-7*3(x+4)+2=0

Wy multiply elements

15x^2(x-18x^2(x-21x(x+2=0

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