3*r*r-22r=16

Solution for 3*r*r-22r=16 equation:

3r*r-22r=16

We move all terms to the left:

3r*r-22r-(16)=0

We add all the numbers together, and all the variables

-22r+3r*r-16=0

Wy multiply elements

3r^2-22r-16=0

a = 3; b = -22; c = -16;
Δ = b2-4ac
Δ = -222-4·3·(-16)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-26}{2*3}=\frac{-4}{6}
=-2/3
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+26}{2*3}=\frac{48}{6}
=8
$