3*m*m-16m-35=0

Solution for 3*m*m-16m-35=0 equation:

3m*m-16m-35=0

We add all the numbers together, and all the variables

-16m+3m*m-35=0

Wy multiply elements

3m^2-16m-35=0

a = 3; b = -16; c = -35;
Δ = b2-4ac
Δ = -162-4·3·(-35)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-26}{2*3}=\frac{-10}{6}
=-1+2/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+26}{2*3}=\frac{42}{6}
=7
$