3(z-4)+10=13-z

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Solution for 3(z-4)+10=13-z equation: 



3(z-4)+10=13-z

We move all terms to the left:

3(z-4)+10-(13-z)=0

We add all the numbers together, and all the variables

3(z-4)-(-1z+13)+10=0

We multiply parentheses

3z-(-1z+13)-12+10=0

We get rid of parentheses

3z+1z-13-12+10=0

We add all the numbers together, and all the variables

4z-15=0

We move all terms containing z to the left, all other terms to the right

4z=15

z=15/4

z=3+3/4

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