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4x-2x(x-2)=-4+5x-13
We move all terms to the left:
4x-2x(x-2)-(-4+5x-13)=0
We add all the numbers together, and all the variables
4x-2x(x-2)-(5x-17)=0
We multiply parentheses
-2x^2+4x+4x-(5x-17)=0
We get rid of parentheses
-2x^2+4x+4x-5x+17=0
We add all the numbers together, and all the variables
-2x^2+3x+17=0
a = -2; b = 3; c = +17;
Δ = b2-4ac
Δ = 32-4·(-2)·17
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{145}}{2*-2}=\frac{-3-\sqrt{145}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{145}}{2*-2}=\frac{-3+\sqrt{145}}{-4} $
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