3(z-2)+10=2(2z+2)+2

Solution for 3(z-2)+10=2(2z+2)+2 equation:

3(z-2)+10=2(2z+2)+2

We move all terms to the left:

3(z-2)+10-(2(2z+2)+2)=0

We multiply parentheses

3z-(2(2z+2)+2)-6+10=0


We calculate terms in parentheses: -(2(2z+2)+2), so:

2(2z+2)+2

We multiply parentheses

4z+4+2

We add all the numbers together, and all the variables

4z+6

Back to the equation:

-(4z+6)


We add all the numbers together, and all the variables

3z-(4z+6)+4=0

We get rid of parentheses

3z-4z-6+4=0

We add all the numbers together, and all the variables

-1z-2=0

We move all terms containing z to the left, all other terms to the right

-z=2

z=2/-1

z=-2