3(x+2)=4(13-x)+3

Solution for 3(x+2)=4(13-x)+3 equation:

3(x+2)=4(13-x)+3

We move all terms to the left:

3(x+2)-(4(13-x)+3)=0

We add all the numbers together, and all the variables

3(x+2)-(4(-1x+13)+3)=0

We multiply parentheses

3x-(4(-1x+13)+3)+6=0


We calculate terms in parentheses: -(4(-1x+13)+3), so:

4(-1x+13)+3

We multiply parentheses

-4x+52+3

We add all the numbers together, and all the variables

-4x+55

Back to the equation:

-(-4x+55)


We get rid of parentheses

3x+4x-55+6=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7