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3(z-10)+4z=-15-2(10-5z)
We move all terms to the left:
3(z-10)+4z-(-15-2(10-5z))=0
We add all the numbers together, and all the variables
3(z-10)+4z-(-15-2(-5z+10))=0
We add all the numbers together, and all the variables
4z+3(z-10)-(-15-2(-5z+10))=0
We multiply parentheses
4z+3z-(-15-2(-5z+10))-30=0
We calculate terms in parentheses: -(-15-2(-5z+10)), so:We add all the numbers together, and all the variables
-15-2(-5z+10)
determiningTheFunctionDomain -2(-5z+10)-15
We multiply parentheses
10z-20-15
We add all the numbers together, and all the variables
10z-35
Back to the equation:
-(10z-35)
7z-(10z-35)-30=0
We get rid of parentheses
7z-10z+35-30=0
We add all the numbers together, and all the variables
-3z+5=0
We move all terms containing z to the left, all other terms to the right
-3z=-5
z=-5/-3
z=1+2/3
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