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6(2y-1)=3(y-1)
We move all terms to the left:
6(2y-1)-(3(y-1))=0
We multiply parentheses
12y-(3(y-1))-6=0
We calculate terms in parentheses: -(3(y-1)), so:We get rid of parentheses
3(y-1)
We multiply parentheses
3y-3
Back to the equation:
-(3y-3)
12y-3y+3-6=0
We add all the numbers together, and all the variables
9y-3=0
We move all terms containing y to the left, all other terms to the right
9y=3
y=3/9
y=1/3
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