3(z+4)=2(3z+5)

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Solution for 3(z+4)=2(3z+5) equation: 



3(z+4)=2(3z+5)

We move all terms to the left:

3(z+4)-(2(3z+5))=0

We multiply parentheses

3z-(2(3z+5))+12=0



We calculate terms in parentheses: -(2(3z+5)), so:

2(3z+5)

We multiply parentheses

6z+10

Back to the equation:

-(6z+10)



We get rid of parentheses

3z-6z-10+12=0

We add all the numbers together, and all the variables

-3z+2=0

We move all terms containing z to the left, all other terms to the right

-3z=-2

z=-2/-3

z=2/3

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