3(z+4)+6=-4(z-1)

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Solution for 3(z+4)+6=-4(z-1) equation: 



3(z+4)+6=-4(z-1)

We move all terms to the left:

3(z+4)+6-(-4(z-1))=0

We multiply parentheses

3z-(-4(z-1))+12+6=0



We calculate terms in parentheses: -(-4(z-1)), so:

-4(z-1)

We multiply parentheses

-4z+4

Back to the equation:

-(-4z+4)



We add all the numbers together, and all the variables

3z-(-4z+4)+18=0

We get rid of parentheses

3z+4z-4+18=0

We add all the numbers together, and all the variables

7z+14=0

We move all terms containing z to the left, all other terms to the right

7z=-14

z=-14/7

z=-2

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