3(c-7)=6c+3(c-7)

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Solution for 3(c-7)=6c+3(c-7) equation: 



3(c-7)=6c+3(c-7)

We move all terms to the left:

3(c-7)-(6c+3(c-7))=0

We multiply parentheses

3c-(6c+3(c-7))-21=0



We calculate terms in parentheses: -(6c+3(c-7)), so:

6c+3(c-7)

We multiply parentheses

6c+3c-21

We add all the numbers together, and all the variables

9c-21

Back to the equation:

-(9c-21)



We get rid of parentheses

3c-9c+21-21=0

We add all the numbers together, and all the variables

-6c=0

c=0/-6

c=0

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