3(z+3)=6z+6-3z+3

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Solution for 3(z+3)=6z+6-3z+3 equation: 



3(z+3)=6z+6-3z+3

We move all terms to the left:

3(z+3)-(6z+6-3z+3)=0

We add all the numbers together, and all the variables

3(z+3)-(3z+9)=0

We multiply parentheses

3z-(3z+9)+9=0

We get rid of parentheses

3z-3z-9+9=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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