3(4-2x)+4(2-3x)=5(1-x)

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Solution for 3(4-2x)+4(2-3x)=5(1-x) equation: 



3(4-2x)+4(2-3x)=5(1-x)

We move all terms to the left:

3(4-2x)+4(2-3x)-(5(1-x))=0

We add all the numbers together, and all the variables

3(-2x+4)+4(-3x+2)-(5(-1x+1))=0

We multiply parentheses

-6x-12x-(5(-1x+1))+12+8=0



We calculate terms in parentheses: -(5(-1x+1)), so:

5(-1x+1)

We multiply parentheses

-5x+5

Back to the equation:

-(-5x+5)



We add all the numbers together, and all the variables

-18x-(-5x+5)+20=0

We get rid of parentheses

-18x+5x-5+20=0

We add all the numbers together, and all the variables

-13x+15=0

We move all terms containing x to the left, all other terms to the right

-13x=-15

x=-15/-13

x=1+2/13

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