3(z+3)=5(z+1)

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Solution for 3(z+3)=5(z+1) equation: 



3(z+3)=5(z+1)

We move all terms to the left:

3(z+3)-(5(z+1))=0

We multiply parentheses

3z-(5(z+1))+9=0



We calculate terms in parentheses: -(5(z+1)), so:

5(z+1)

We multiply parentheses

5z+5

Back to the equation:

-(5z+5)



We get rid of parentheses

3z-5z-5+9=0

We add all the numbers together, and all the variables

-2z+4=0

We move all terms containing z to the left, all other terms to the right

-2z=-4

z=-4/-2

z=+2

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