2(k-1)=2(k+3)

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Solution for 2(k-1)=2(k+3) equation: 



2(k-1)=2(k+3)

We move all terms to the left:

2(k-1)-(2(k+3))=0

We multiply parentheses

2k-(2(k+3))-2=0



We calculate terms in parentheses: -(2(k+3)), so:

2(k+3)

We multiply parentheses

2k+6

Back to the equation:

-(2k+6)



We get rid of parentheses

2k-2k-6-2=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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