3(z+12)=51

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Solution for 3(z+12)=51 equation: 



3(z+12)=51

We move all terms to the left:

3(z+12)-(51)=0

We multiply parentheses

3z+36-51=0

We add all the numbers together, and all the variables

3z-15=0

We move all terms containing z to the left, all other terms to the right

3z=15

z=15/3

z=5

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