3(z+1)=5(z-4)

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Solution for 3(z+1)=5(z-4) equation: 



3(z+1)=5(z-4)

We move all terms to the left:

3(z+1)-(5(z-4))=0

We multiply parentheses

3z-(5(z-4))+3=0



We calculate terms in parentheses: -(5(z-4)), so:

5(z-4)

We multiply parentheses

5z-20

Back to the equation:

-(5z-20)



We get rid of parentheses

3z-5z+20+3=0

We add all the numbers together, and all the variables

-2z+23=0

We move all terms containing z to the left, all other terms to the right

-2z=-23

z=-23/-2

z=11+1/2

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