3(z+1)=4z-11

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Solution for 3(z+1)=4z-11 equation: 



3(z+1)=4z-11

We move all terms to the left:

3(z+1)-(4z-11)=0

We multiply parentheses

3z-(4z-11)+3=0

We get rid of parentheses

3z-4z+11+3=0

We add all the numbers together, and all the variables

-1z+14=0

We move all terms containing z to the left, all other terms to the right

-z=-14

z=-14/-1

z=+14

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