-6(x-4)+1=3(x-5)

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Solution for -6(x-4)+1=3(x-5) equation: 



-6(x-4)+1=3(x-5)

We move all terms to the left:

-6(x-4)+1-(3(x-5))=0

We multiply parentheses

-6x-(3(x-5))+24+1=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

-6x-(3x-15)+25=0

We get rid of parentheses

-6x-3x+15+25=0

We add all the numbers together, and all the variables

-9x+40=0

We move all terms containing x to the left, all other terms to the right

-9x=-40

x=-40/-9

x=4+4/9

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