3(y-6)+18=12y-60

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Solution for 3(y-6)+18=12y-60 equation: 



3(y-6)+18=12y-60

We move all terms to the left:

3(y-6)+18-(12y-60)=0

We multiply parentheses

3y-(12y-60)-18+18=0

We get rid of parentheses

3y-12y+60-18+18=0

We add all the numbers together, and all the variables

-9y+60=0

We move all terms containing y to the left, all other terms to the right

-9y=-60

y=-60/-9

y=6+2/3

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