3(x-5)+2(x+1)=4(x+2)

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Solution for 3(x-5)+2(x+1)=4(x+2) equation: 



3(x-5)+2(x+1)=4(x+2)

We move all terms to the left:

3(x-5)+2(x+1)-(4(x+2))=0

We multiply parentheses

3x+2x-(4(x+2))-15+2=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

5x-(4x+8)-13=0

We get rid of parentheses

5x-4x-8-13=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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