3(y-5)=7y-27

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Solution for 3(y-5)=7y-27 equation:



3(y-5)=7y-27
We move all terms to the left:
3(y-5)-(7y-27)=0
We multiply parentheses
3y-(7y-27)-15=0
We get rid of parentheses
3y-7y+27-15=0
We add all the numbers together, and all the variables
-4y+12=0
We move all terms containing y to the left, all other terms to the right
-4y=-12
y=-12/-4
y=+3

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