3(x-5)=2(3x+1)=45

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Solution for 3(x-5)=2(3x+1)=45 equation: 



3(x-5)=2(3x+1)=45

We move all terms to the left:

3(x-5)-(2(3x+1))=0

We multiply parentheses

3x-(2(3x+1))-15=0



We calculate terms in parentheses: -(2(3x+1)), so:

2(3x+1)

We multiply parentheses

6x+2

Back to the equation:

-(6x+2)



We get rid of parentheses

3x-6x-2-15=0

We add all the numbers together, and all the variables

-3x-17=0

We move all terms containing x to the left, all other terms to the right

-3x=17

x=17/-3

x=-5+2/3

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