3(y-5)=-8y+40

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Solution for 3(y-5)=-8y+40 equation: 



3(y-5)=-8y+40

We move all terms to the left:

3(y-5)-(-8y+40)=0

We multiply parentheses

3y-(-8y+40)-15=0

We get rid of parentheses

3y+8y-40-15=0

We add all the numbers together, and all the variables

11y-55=0

We move all terms containing y to the left, all other terms to the right

11y=55

y=55/11

y=5

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