2y+40=-8(y+5)

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Solution for 2y+40=-8(y+5) equation: 



2y+40=-8(y+5)

We move all terms to the left:

2y+40-(-8(y+5))=0



We calculate terms in parentheses: -(-8(y+5)), so:

-8(y+5)

We multiply parentheses

-8y-40

Back to the equation:

-(-8y-40)



We get rid of parentheses

2y+8y+40+40=0

We add all the numbers together, and all the variables

10y+80=0

We move all terms containing y to the left, all other terms to the right

10y=-80

y=-80/10

y=-8

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