3(y-5)/4-4y=3-(y-3)/2

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Solution for 3(y-5)/4-4y=3-(y-3)/2 equation: 



3(y-5)/4-4y=3-(y-3)/2

We move all terms to the left:

3(y-5)/4-4y-(3-(y-3)/2)=0

We add all the numbers together, and all the variables

-4y+3(y-5)/4-(3-(y-3)/2)=0

We calculate fractions


-4y+3y/()+(-(3-(y-3)*4)/()=0



We calculate terms in parentheses: +(-(3-(y-3)*4)/(), so:

-(3-(y-3)*4)/(

We multiply all the terms by the denominator


-(3-(y-3)*4)



We calculate terms in parentheses: -(3-(y-3)*4), so:

3-(y-3)*4

determiningTheFunctionDomain
-(y-3)*4+3

We multiply parentheses

-4y+12+3

We add all the numbers together, and all the variables

-4y+15

Back to the equation:

-(-4y+15)



We get rid of parentheses

4y-15

Back to the equation:

+(4y-15)



We get rid of parentheses

-4y+3y/()+4y-15=0

We multiply all the terms by the denominator


-4y*()+3y+4y*()-15*()=0

We add all the numbers together, and all the variables

3y-4y*()+4y*()=0

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