7+1/5b=3/10b

Solution for 7+1/5b=3/10b equation:

7+1/5b=3/10b

We move all terms to the left:

7+1/5b-(3/10b)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



Domain of the equation: 10b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

1/5b-(+3/10b)+7=0

We get rid of parentheses

1/5b-3/10b+7=0

We calculate fractions


10b/50b^2+(-15b)/50b^2+7=0

We multiply all the terms by the denominator


10b+(-15b)+7*50b^2=0

Wy multiply elements

350b^2+10b+(-15b)=0

We get rid of parentheses

350b^2+10b-15b=0

We add all the numbers together, and all the variables

350b^2-5b=0

a = 350; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·350·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*350}=\frac{0}{700}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*350}=\frac{10}{700}
=1/70
$