3(y-4)=2y+3

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Solution for 3(y-4)=2y+3 equation: 



3(y-4)=2y+3

We move all terms to the left:

3(y-4)-(2y+3)=0

We multiply parentheses

3y-(2y+3)-12=0

We get rid of parentheses

3y-2y-3-12=0

We add all the numbers together, and all the variables

y-15=0

We move all terms containing y to the left, all other terms to the right

y=15

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