.2=(6+2x)/12+x

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Solution for .2=(6+2x)/12+x equation: 



.2=(6+2x)/12+x

We move all terms to the left:

.2-((6+2x)/12+x)=0



Domain of the equation: 12+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-12

x!=-12/1

x!=-12

x∈R



We add all the numbers together, and all the variables

-((2x+6)/12+x)+.2=0

We add all the numbers together, and all the variables

-((2x+6)/12+x)+0.2=0

We multiply all the terms by the denominator


-((2x+6)+(0.2)*12+x)=0



We calculate terms in parentheses: -((2x+6)+(0.2)*12+x), so:

(2x+6)+(0.2)*12+x

determiningTheFunctionDomain
(2x+6)+x+(0.2)*12

We add all the numbers together, and all the variables

x+(2x+6)+2.4

We get rid of parentheses

x+2x+6+2.4

We add all the numbers together, and all the variables

3x+8.4

Back to the equation:

-(3x+8.4)



We get rid of parentheses

-3x-8.4=0

We move all terms containing x to the left, all other terms to the right

-3x=8.4

x=8.4/-3

x=-2+2.4/3

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